# How do you find the vertex and axis of symmetry of #y=5/4(x+2)^2 -1#?

##### 1 Answer

Jun 28, 2017

Vertex is

#### Explanation:

This is the equation of a horizontal parabola in vertex form i.e.

where vertex is

Hence vertex and axis of symmetry of

or

are

graph{((x+2)^2-4-4y)(x+2)((x+2)^2+(y+1)^2-0.02)=0 [-13, 7, -4.28, 5.72]}